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<h3>We have to practice everyday.</h3>
<p><b>practice makes perfect.</b></p>
<p><i>I love this saying.</i></p>
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\[
\begin{array}{|c|c|c|}
\hline
\text{Set} & \text{Operation} & \text{Identity} \\
\hline
\mathbb{Z} & + & 0 \\
\hline
\mathbb{Q} & + & 0 \\
\hline
\mathbb{R} & + & 0 \\
\hline
\mathbb{Z} & \times & 1 \\
\hline
\mathbb{Q} & \times & 1 \\
\hline
\mathbb{R} & \times & 1 \\
\hline
\end{array}
\]
\[ \begin{matrix} a & b \newline c & d\end{matrix}\]
\[ \begin{vmatrix} a & b \newline c & d\end{vmatrix}\]
\[ \begin{pmatrix} a & b \newline c & d\end{pmatrix}\]
\[ \begin{bmatrix} a & b \newline c & d\end{bmatrix}\]
\[ \begin{align*} 2x+y=3 \tag{1}\\ 3x-y=5 \tag{2} \end{align*} \]
\[\begin{cases} x+y=5 \\ x-y=3 \end{cases}\]
\[ \binom nr \]
\[ _{n} {\rm C} _{r}\]
\[ _{n} {\rm P} _{r}\]
\[ _{n} {\rm H} _{r}\]
\[
ax^2 +bx + c= 0 \]
\[ x= {{-b \pm \sqrt{b^2-4ac}} \over {2a}}\]
\( \sqrt{b^2 - \color{red}4 a c} = 0 \)
\[ \begin{align*} \sqrt{b^2 - 4 a c } = 0 \; \; \;\; \left(a > 0, \;b > 0,\; c >0 \right) \end{align*}\]
\[ \begin{align*} \int _{a} ^{b} f(x) \,{\rm d} x = {\bf F} (b) - {\bf F} (a) \end{align*} \]
\[{\bf a} \cdot {\bf b}\]
\[{\bf a} \times {\bf b}\]
\[ \vec{a} \times \vec{b}\]
\[\vec F\left( {x,y} \right) = - y\,\vec i + x\,\vec j\]
\[\begin{align*}\vec F\left( {\frac{1}{2},\frac{1}{2}} \right) & = - \frac{1}{2}\vec i + \frac{1}{2}\vec j\\ \vec F\left( {\frac{1}{2}, - \frac{1}{2}} \right) & = - \left( { - \frac{1}{2}} \right)\vec i + \frac{1}{2}\vec j = \frac{1}{2}\vec i + \frac{1}{2}\vec j\\\vec F\left( {\frac{3}{2},\frac{1}{4}} \right) & = - \frac{1}{4}\vec i + \frac{3}{2}\vec j\end{align*}\]
\[\nabla f = \left\langle {{f_x},{f_y},{f_z}} \right\rangle\]
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We have to practice everyday.
practice makes perfect.
I love this saying.
\[ \begin{array}{|c|c|c|} \hline \text{Set} & \text{Operation} & \text{Identity} \\ \hline \mathbb{Z} & + & 0 \\ \hline \mathbb{Q} & + & 0 \\ \hline \mathbb{R} & + & 0 \\ \hline \mathbb{Z} & \times & 1 \\ \hline \mathbb{Q} & \times & 1 \\ \hline \mathbb{R} & \times & 1 \\ \hline \end{array} \] \[ \begin{matrix} a & b \newline c & d\end{matrix}\] \[ \begin{vmatrix} a & b \newline c & d\end{vmatrix}\] \[ \begin{pmatrix} a & b \newline c & d\end{pmatrix}\] \[ \begin{bmatrix} a & b \newline c & d\end{bmatrix}\] \[ \begin{align*} 2x+y=3 \tag{1}\\ 3x-y=5 \tag{2} \end{align*} \] \[\begin{cases} x+y=5 \\ x-y=3 \end{cases}\] \[ \binom nr \] \[ _{n} {\rm C} _{r}\] \[ _{n} {\rm P} _{r}\] \[ _{n} {\rm H} _{r}\] \[ ax^2 +bx + c= 0 \] \[ x= {{-b \pm \sqrt{b^2-4ac}} \over {2a}}\] \( \sqrt{b^2 - \color{red}4 a c} = 0 \) \[ \begin{align*} \sqrt{b^2 - 4 a c } = 0 \; \; \;\; \left(a > 0, \;b > 0,\; c >0 \right) \end{align*}\] \[ \begin{align*} \int _{a} ^{b} f(x) \,{\rm d} x = {\bf F} (b) - {\bf F} (a) \end{align*} \] \[{\bf a} \cdot {\bf b}\] \[{\bf a} \times {\bf b}\] \[ \vec{a} \times \vec{b}\] \[\vec F\left( {x,y} \right) = - y\,\vec i + x\,\vec j\] \[\begin{align*}\vec F\left( {\frac{1}{2},\frac{1}{2}} \right) & = - \frac{1}{2}\vec i + \frac{1}{2}\vec j\\ \vec F\left( {\frac{1}{2}, - \frac{1}{2}} \right) & = - \left( { - \frac{1}{2}} \right)\vec i + \frac{1}{2}\vec j = \frac{1}{2}\vec i + \frac{1}{2}\vec j\\\vec F\left( {\frac{3}{2},\frac{1}{4}} \right) & = - \frac{1}{4}\vec i + \frac{3}{2}\vec j\end{align*}\] \[\nabla f = \left\langle {{f_x},{f_y},{f_z}} \right\rangle\]반응형
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